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In the previous question, let V0 be the volume of each container. All other details remain the same. The number of moles of gas in the container at temperature 2T0 will be(a) p0V0 / 2RT0(b) p0V0 / RT0(c) 2p0V0 / 3RT0(d) p0V0 / 3RT0 |
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Answer» Correct Answer is: (c) 2p0V0 / 3RT0 p1V = n1RT1, p2V = n2RT2, p(2V) = (n1 + n2)RT |
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