1.

In the reaction 2FeC1_(2) + SnC1_(2) to 2FeC1_(2) + SnC1_(4)

Answer»

`Fe^(+1)` REDUCED to `Fe^(+2)`
`Sn^(+2)` is reduced to `Sn^(+1)`
`Sn^(+2)` oxidized to `Sn`
`Fe^(+1)` gains two electrons

Solution :`2 overset (+3) (FeC1_(3)) + overset (+2) (SNC1_(2)) to overset (+2) (2FeC1_(2)) + overset (+4) (SnC1_(4)`
`Fe^(3+)` is reduced to `Fe^(2+)` (GAIN of ELECTRON) and `Sn^(2+)` is oxidised to `Sn^(4+)` (LOSS of two electrons)


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