1.

In the reaction N_(2)O_(4) hArr 2NO_(2), the dissociation of N_(2)O was found to be 40 per cent at equilibrium when the reaction is conducted in a 2 L container at 300 K. Find the equilibrium constant and the number of moles of reactants and products.

Answer»

Solution :`{:(N_(2)O_(4), hArr,2NO_(2)),("Initial moles "," "1," "0):}`
Number of moles at equilibrium1-0.4=0.6 `""` 0.8
Concentration at equilibrium `0.6//2=0.3 ""0.8//2=0.4`
`THEREFORE K_(C)=([NO_(2)]^(2))/([N_(2)O_(4)])=((0.4)^(2))/(0.3)=0.533` mol/L


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