1.

In triangle ABC, angle A is greater than angle B. If the measure of angles A and B satisfy the equation `3sinx-4sin^3x-k=0`. (A) `pi/3` (B) `pi/2` (C) `(2pi)/3` (D) `(5pi)/6`

Answer» `A>B`
`3sinx-4sin^3x-k=0`
`sin3x=k`
`sin3A=k`
`sin3B=k`
`sin3A-sin3B=0`
`2cos((3A+3B)/2)sin((3A-3B)/2)=0`
`A+B=60`
Now, we know
`A+B+C=180`
`C=120`.


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