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In triangle ABC, prove that the maximum value of `tanA/2tanB/2tanC/2i s R/(2s)` |
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Answer» `tan(A/2)tan(B/2)tan(C/2)` `sqrt(((s-b)(s-c))/(s(s-a)))sqrt(((s-a)(s-c))/(s(s-b)))sqrt((s-a)(s-b))/(s(s-c)` `sqrt((s(s-a)(s-b)(s-c))/s^4` `/_/s^2=r/s<=R/(2s)`. |
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