In `triangleABC, a cosB-b cosA=`A. `(a^(2)-b^(2))`B. `b^(2)-c^(2)`C. ` – InterviewSolution

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1.	In `triangleABC, a cosB-b cosA=`A. `(a^(2)-b^(2))`B. `b^(2)-c^(2)`C. `c^(2)-a^(2)`D. `a^(2)+b^(2)+c^(2)`
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