In `triangleABC, (b+c)cosA+(c+a)cosB+(a+b)cosC=`A. `a+b+c`B. `2(a+b+c) – InterviewSolution

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1.	In `triangleABC, (b+c)cosA+(c+a)cosB+(a+b)cosC=`A. `a+b+c`B. `2(a+b+c)`C. `(a+b+c)/(2)`D. `(a+b+c)/(4)`
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