In `triangleABC, (c+a-b)tan((B)/(2))=`A. `(A(triangleABC))/(s)`B. `(2A – InterviewSolution

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1.	In `triangleABC, (c+a-b)tan((B)/(2))=`A. `(A(triangleABC))/(s)`B. `(2A(triangleABC))/(s)`C. `A(triangleABC)`D. `2A(triangleABC)`
Answer» Correct Answer - B

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