1.

In `triangleABC, cos((A-B)/(2))=`A. `((a+b)/(c))sin((C)/(2))`B. `((a+b)/(2c))sin((C)/(2))`C. `((a+b)/(c))cos((C)/(2))`D. `((a+b)/(2c))cos((C)/(2))`

Answer» Correct Answer - A


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