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| 1. |
In `triangleABC, (cosA)/(c cosB+bcosC)+(cosB)/(acosC+ccosA)+(cosC)/(acosB+bcosA)=`A. `(a^(2)+b^(2)-c^(2))/(4)`B. `(a^(2)+b^(2)-c^(2))/(2)`C. `(a^(2)+b^(2)+c^(2))/(4abc)`D. `(a^(2)+b^(2)+c^(2))/(2abc)` |
| Answer» Correct Answer - D | |