In `triangleABC, s(s-c)tan((C)/(2))=`A. `(A(triangleABC))/(2)`B. `(2A( – InterviewSolution

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1.	In `triangleABC, s(s-c)tan((C)/(2))=`A. `(A(triangleABC))/(2)`B. `(2A(triangleABC))/(4)`C. `A(triangleABC)`D. `2A(triangleABC)`
Answer» Correct Answer - C

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