1.

In `triangleABC, sin((B-C)/(2))=`A. `2((b-c)/(a))cos((A)/(2))`B. `((b-c)/(a))cos((A)/(2))`C. `2((c-b)/(a))cos((A)/(2))`D. `((c-b)/(a))cos((A)/(2))`

Answer» Correct Answer - B


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