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In what ratio should `._(17)CI^(37)` and `._(17)CI^(35)` be presents so as to obtain `._(17)CI^(35.5)`?A. `1:2`B. `1:1`C. `1:3`D. `3:1` |
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Answer» Correct Answer - C Let `x%` of `CI^(17) `and `(100 - x)%` of` CI^(15)` be presents in `._(17)CI^(35.5)` `:. 35.5 = (x xx 37 + (100 - x) xx 35)/(100)` Solve for x, `x = 25` `:. % of CI^(37) = 25` `:. % of CI^(o+) = 75` `:. Ratio is 1:3` |
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