1.

In what ratio should `._(17)CI^(37)` and `._(17)CI^(35)` be presents so as to obtain `._(17)CI^(35.5)`?A. `1:2`B. `1:1`C. `1:3`D. `3:1`

Answer» Correct Answer - C
Let `x%` of `CI^(17) `and `(100 - x)%` of` CI^(15)` be presents in `._(17)CI^(35.5)`
`:. 35.5 = (x xx 37 + (100 - x) xx 35)/(100)`
Solve for x,
`x = 25`
`:. % of CI^(37) = 25`
`:. % of CI^(o+) = 75`
`:. Ratio is 1:3`


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