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Insulin `(C_(2)H_(10)O_(5))_(n)` is dissolved in a suitable solvent and the osmotic pressure `(pi)` of solutions of various concentrations `(g//cm^(3))C` is measured at `20^(@)C`. The slope of a plot of `pi` against `C` is found to be `4.65 xx 10^(-3)`. The molecular weight of insulin is:A. `4.8xx10^(5)`B. `9xx10^(5)`C. `3xx10^(5)`D. `5.17xx10^(6)` |
Answer» Correct Answer - D `piV=(w_(B))/(m_(B))xxRT` `pi=(w_(B)/(V))(RT)/(m_(B))` `pi=cxx(RT)/(m_(B))xx1000`…..(i) where C = concentrated in g/cc, Comparing eqs.(i)and(ii),…(iii) Slope `=(RT)/(m_(R))xx1000` `m_(B)=(RT)/(Slope)xx1000` `(0.0821xx293xx1000)/(4.65xx10^(-3))=5.17xx10^(6)J` |
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