InterviewSolution
Saved Bookmarks
| 1. |
` int _(0)^(2pi) (sin x + |sin x|)dx` is equal to |
|
Answer» Correct Answer - B ` int _(0)^(2pi) ( sin x + | sin x| ) dx ` ` int _(0)^(pi) ( sin x + sin x) dx + int _(pi)^(2pi) (sin x - sin x) dx ` ` = int _(0)^(pi) 2 sin x dx + int _(pi)^(2pi) 0 dx = 2 [ - cos x] _(0)^(pi) +0` ` = int _(0)^(pi) 2 sin x dx + int _(pi)^(2pi) 0 dx = 2 [ - cos x ] _(0)^(pi) + 0 ` ` = - 2 ( cos pi - cos 0) = -2 (-1-1) = 4` |
|