1.

` int _(0)^(2pi) (sin x + |sin x|)dx` is equal to

Answer» Correct Answer - B
` int _(0)^(2pi) ( sin x + | sin x| ) dx `
` int _(0)^(pi) ( sin x + sin x) dx + int _(pi)^(2pi) (sin x - sin x) dx `
` = int _(0)^(pi) 2 sin x dx + int _(pi)^(2pi) 0 dx = 2 [ - cos x] _(0)^(pi) +0`
` = int _(0)^(pi) 2 sin x dx + int _(pi)^(2pi) 0 dx = 2 [ - cos x ] _(0)^(pi) + 0 `
` = - 2 ( cos pi - cos 0) = -2 (-1-1) = 4`


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