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`int_(0)^(2pi)|sinx|dx=?`A. `2`B. `4`C. `1`D. none of these |
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Answer» `I=int_(0)^(pi)sinxdx+int_(pi)^(2pi)-sinxdx`. `=[-cosx]_(0)^(pi)+[cosx]_(pi)^(2pi)=(2+2)=4`. |
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