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`int _(0)^(pi//2) (cosx)/(1+sinx)dx` is equal toA. log 2B. 2 log 2C. `(log 2)^(2)`D. `1/2 log2` |
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Answer» Correct Answer - A Let ` I = int _(0)^(pi//2)(cosx)/(1+sinx)dx` ` = [ log (1+sin x)]_(0)^(pi//2)= log 2- log 1 = log 2` |
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