1.

`int_(0)^(pi//2)sin^(2)xdx=?`A. `(pi)/(3)`B. `(pi)/(4)`C. `(pi)/(2)`D. `(2pi)/(3)`

Answer» `I=(1)/(2)*int_(0)^(pi//2)(1-cos2x)dx=(1)/(2)[x-(sin2x)/(2)]_(0)^(pi//2)=(pi)/(4)`.


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