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`int_(0)^(pi//2)xcosxdx` `=?`A. `(pi)/(2)`B. `((pi)/(2)-1)`C. `((pi)/(2)+1)`D. none of these |
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Answer» Integrating by parts, we get : `I=int_(0)^(pi//2)xcosxdx=[xsinx]_(0)^(pi//2)-int_(0)^(pi//2)(1*sinx)dx=(pi)/(2)+[cosx]_(0)^(pi//2)-((pi)/(2)-1)`. |
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