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` int _(0)^(pi//4) log ((sin x+ cos x)/(cosx))dx ` is equal toA. `(pi)/(8)log2`B. `(pi)/(4)log2`C. `log2`D. `(pi)/(2)log2` |
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Answer» Correct Answer - A Let ` l = int _(0)^(pi//4) log ((sin x + cos x)/(cos x)) dx` ` l =- int _(0)^(pi//4) log (1+tan x ) dx" " ` ` = int _(0)^(pi//4) log [ 1 + tan (pi/4 -x) ] dx` ` = int _(0)^(pi//4) log (1+ (tan pi//4-tan x)/(1+tan pi //4 tanx))dx` ` = int _(0)^(pi//4) log (1+ (1-tanx)/(1+tan x)) dx` ` rArr l = int _(0)^(pi//4) log (2/(1+tan x))dx" "` ...(ii) On adding Eqs. (i) and (ii) , we get ` 2l = int _(0)^(pi//4) log 2 dx = log 2 (pi/4)` ` rArr l = pi/8 log 2 ` |
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