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` int _(0)^(pi//6) (2+3x^(2))cos 3 xdx ` is equal toA. `(1)/(36)(pi+16)`B. `(1)/(36)(pi-16)`C. `(1)/(36)(pi^(2)-16)`D. `(1)/(36)(pi^(2)+16)` |
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Answer» Correct Answer - D ` int _(0)^(pi//6) (2+3x^(2) ) cos 3x` ` = [ (sin 3x)/3 (2+3x^(2)) ]_(0)^(pi/6) - int _(0)^(pi//6) (sin 3x)/3 . 6x dx ` ` = 1/36 (pi^(2)+16)` |
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