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` int _(0)^(pi) | cos x| dx ` is equal toA. `(1)/(2)`B. `-2`C. 1D. 2 |
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Answer» Correct Answer - D ` int _(0)^(pi) | cos x| dx = int _(0)^(pi//2) cos x dx - int _(pi//2)^(pi) cos x dx ` ` = [ sin x ] _(0)^(pi//2) - [ sin x] _(pi//2)^(pi)` ` = sin pi/2 - sin 0 - sin pi + sin. pi/2 ` ` = 2 sin. pi/2 = 2 ` |
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