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`int_(0)^(pi)|cosx|dx=?`A. `2`B. `(3)/(2)`C. `1`D. `0` |
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Answer» `I=int_(0)^(pi//2)cosxdx+int_(pi//2)^(pi)-cosxdx`. `=[sinx]_(0)^(pi//2)-[sinx]_(pi//2)^(pi)=1-(0-1)=2`. |
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