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`int_(0)^(pi)(dx)/((1+sinx))=?`A. `(1)/(2)`B. `1`C. `2`D. `0` |
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Answer» `I=int_(0)^(pi)((1-sinx))/((1-sin^(2)x))dx=int_(0)^(pi)((1-sinx))/(cos^(2)x)dx` `=int_(0)^(pi)[sec^(2)x-secxtanx]dx=[tanx-secx]_(0)^(pi)=2`. |
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