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`int_(0)^(pi)(sin2xcos3x)dx=?`A. `(4)/(5)`B. `-(4)/(5)`C. `(5)/(12)`D. `-(12)/(5)` |
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Answer» `2cosAsinB=sin(A+B)-sin(A-B)` `:.I=(1)/(2)int_(0)^(pi)(sin5x-sinx)dx=(1)/(2)*[(-cos5x)/(5)+cosx]_(0)^(pi)=(-4)/(5)`. |
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