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`int e^(tan theta)(sec theta- sin theta) d theta` is equal to: (A) `-e^(tantheta) sintheta+c` (B) `e^(tantheta) sintheta+c` (C) `-e^(tantheta) sectheta+c` (D) `e^(tantheta) costheta+c` |
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Answer» `e^(tantheta)sintheta=e^tantheta sec^2thetasintheta+e^tantheta*costheta` `e^tantheta*costheta=e^tantheta sec^2theta*costheta-e^tantheta*sintheta` `=e^tantheta(sectheta-sinntheta)`. |
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