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`int_(0)^(pi//2) cosx e^(sinx) dx` is equal toA. `e+1`B. `e-1`C. `e`D. `-e` |
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Answer» Correct Answer - A Let ` I = int_(0)^(pi//2)cosxe^(sinx)dx` Put `sinx = t rArr cosx dx = dt` As `x rarr 0` then `t rarr 0` and `x rarr pi//2`, then `t rarr 1` `:. I = int_(0)^(t)e^(t)dt = [e^(t)]_(0)^(1)` `= e^(1) - e^(0)=e-1` |
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