\(\int \frac{1 + x \sqrt{x + x^2}}{\sqrt{x} + \sqrt{1 + x}}.dx =\)∫ (1 + x √(x + x2))/(√x + √1 + x)(a) \(\frac{1}{2} \sqrt{x + 1} + c\)(b) \(\frac{2}{3} (x + 1) ^{\frac{3}{2}}+ c\)(c) \(\sqrt{x + 1} + c\)(d) \(2 (x + 1) ^{\frac{3}{2}}+ c\)

\(\int \frac{1 + x \sqrt{x + x^2}}{\sqrt{x} + \sqrt{1 + x}}.dx =\)∫

1.	\(\int \frac{1 + x \sqrt{x + x^2}}{\sqrt{x} + \sqrt{1 + x}}.dx =\)∫ (1 + x √(x + x2))/(√x + √1 + x)(a) \(\frac{1}{2} \sqrt{x + 1} + c\)(b) \(\frac{2}{3} (x + 1) ^{\frac{3}{2}}+ c\)(c) \(\sqrt{x + 1} + c\)(d) \(2 (x + 1) ^{\frac{3}{2}}+ c\)
Answer» Correct answer is (b) \(\frac{2}{3} (x + 1) ^{\frac{3}{2}}+ c\)