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\(\int \frac{e^x (x - 1)}{x^2}.dx =\)∫ (ex(x - 1))/x2 . dx =(a) \(\frac{e^x}{x} + c\)(b) \(\frac{e^x}{x^2} + c\)(c) \((x - \frac{1}{x})e^x + c\)(d) x e-x + c |
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Answer» Correct answer is (a) \(\frac{e^x}{x} + c\) |
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