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`int_(pi)^(2pi)|sinx|dx=?`A. `0`B. `1`C. `2`D. none of these

Answer» `pi le x lt 2pi implies sin x le 0 implies |sinx|=-sinx`
`:.I=int_(pi)^(2pi)-sinxdx=[cosx]_(pi)^(2pi)=2`.


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