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Ionisation energy of `He^+` is `19.6 xx 10^-18 J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^( 2 +)` is.A. `4.41xx10^(-16)J atom^(-1)`B. `-4.41xx10^(-17) J atom^(-1)`C. `-2.2xx10^(-15)J atom^(-1)`D. `8.82xx10^(-17)J atom^(-1)` |
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Answer» Correct Answer - B `IE=-E_(1)` `E_(1) for He^(+)=-19.6xx10^(-18)Jat om ^(-1)` `(E_(1))_(He^(+))/((E_(1))_(Li^(2+)))=(Z_(He^(+)))^(2)/((Z_(Li^(2+)))^(2))rArr (-19.6xx10^(-18))/((E_(1))_(Li^(2+)))=4/9` `E_(1)(Li^(2+))=(-19.6xx9xx10^(-18))/4` `-4.41xx10^(-17)Jat om^(-1)` |
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