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Ionisation energy of `He^+` is `19.6 xx 10^-18 J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^( 2 +)` is.A. `4.41 xx 10^(-16)J "atom"^(-1)`B. `-4.41 xx 10^(-17)J "atom"^(-1)`C. `-2.2 xx 10^(-15)J "atom"^(-1)`D. `-8.83 xx 10^(-17)J "atom"^(-1)` |
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Answer» Correct Answer - B `I.E =- E_(1), E_(n) prop (z^(2))/(n^(2)) rArr ((E_(1))_(He^(+)))/((E_(1))_(Li^(+2))) =((z_(He^(+)))^(2))/((z_(Li^(+2)))^(2))` |
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