1.

Ionisation energy of `He^+` is `19.6 xx 10^-18 J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^( 2 +)` is.A. `4.41xx10^(-16) J atom^(-1)`B. `-4.41xx10^(-17) J atom^(-1)`C. `-2.2xx10^(-15) J atom^(-1)`D. `8.82xx10^(-17) J atom^(-1)`

Answer» Correct Answer - 2
I.E. of `He^(+)=19.6xx10^(-18)J atom^(-1)`
I.E. `=-E_(1)`
`E_(1)` for `He^(+)` is `=-19.6xx10^(-18) J atom^(-1)`
`((E_(1))_(He^(+)))/((E_(1))_(Li^(3+)))=((Z_(He^(+)))^(2))/((Z_(Li^(2-)))^(2))rArr (-19.6xx10^(-18))/((E_(1))_(Li^(2-)))=4/9`
`E_(1)(Li^(2+))=(-19.6xx9xx10^(-18))/(4)=-44.1xx10^(-18)=-4.41xx`0^(-17) J atom^(-1)`


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