1.

Iqbal treated a lustrous, divalent element M with sodium hydroxide, He observed the formation of bubbles in reaction mixture. He made the same observations when this element was treated with hydrochloric acid, Suggest how can he identify the produced gas. Write chemical equations for both the reactions.

Answer»

Solution :The ELEMENT is a METAL
`M+2NaOH to Na_2MO_2+H_2`
`M+2HCl to MCl_2+H_2`
The produced gas can be identified by BRINGING a burning matchstick near the reaction vessel . The gas burns with a pop SOUND The confirms that the gas is `H_2`.


Discussion

No Comment Found