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It is given that `E=(2.859)/lambda cal//mol` The energy associated with radiation of wavelength `4xx10^(-5)` m will beA. `71.5 kcal//mol`B. `35.75kcal//mol`C. `32.0 kcal//mol`D. `7.15 kcal//mol` |
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Answer» Correct Answer - A Given `E=(2.859)/lambdacal//mol` `lambda=4xx10^(-7)` `E=(2.859 cal//mol)/(4xx10^(-5)m)=71.5kcal//mol` |
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