1.

Judge the equivalent resistance when the following are connected in parallel: 1 Omega and 10^(6)Omega

Answer»

Solution :(a) Less than 1`Omega` (but approximately `1 Omega`)
(b) less than `1 Omega` (but approximately `1 Omega`)
EXPLANATION: When RESISTORS are CONNECTED in parallel. the equivalent resistance is less than the least resistance (here in both the cases it is 1 `Omega`) connected in the combination.
Here , `R_1 = 1Omega and R_2 = 10^6 Omega`
The equivalent resistance `R_p` of the parallel combination is given by.
`1/R_P = 1/R_1 + 1/R_2`
`:. R_p = (R_1 xx R_2)/(R_1 + R_2)`
`= (1 xx 10^6)/(1 + 10^6)`
`= (1000000)/(1000001) ~~ 1 Omega`


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