Jupiter has a mass 318 times that of earth, and its radius is 11.2 times the earth's radius Estimate the escape velocity of a body from Jupiter's surface, given that the escape velocity from the earth's surface 11.2 kms^(-1).

Jupiter has a mass 318 times that of earth, and its radius is 11.2 tim

1.	Jupiter has a mass 318 times that of earth, and its radius is 11.2 times the earth's radius Estimate the escape velocity of a body from Jupiter's surface, given that the escape velocity from the earth's surface 11.2 kms^(-1).
Answer» Solution :Escape VELOCITY from the earth's surface is `v_e =sqrt((2GM)/(R )) = 11.2 kms^(-1)` Escape velocity from JUPITER's surface will be `v_e' = sqrt((2GM')/(R'))` But `M' = 318 M, R'= 11.2 R` `v_e' = sqrt((2G(318M))/(11.2))= sqrt((2GM)/(R )xx(318)/(11.2))` `v_e'xx sqrt((318)/(11.2))= 11.2xx sqrt((318)/(11.2))= 59.7 kms^(-1)`.