InterviewSolution
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InterviewSolution
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k के किस मान के लिए बिन्दु `(k, 2-2k), (-k+1, 2k)` तथा `(-4-k, 6-2k)` संरेख होंगे ? |
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Answer» माना `A -= (x_(1), y_(1)) = (k, 2-2k)` `B -= (x_(2), y_(2)) = (-k +1, 2k)` ` C-=(x_(3), y_(3)) = (-4-k, 6-2k)` तीनो बिंदुओं को संरेख होने के लिए, `x_(1)(y_(2) - y_(3)) + x_(2)(y_(3) -y_(1)) + x_(3)(y_(1) - y_(2)) = 0` `rArr k(2k - 6 + 2k) + (-k+1) (6-2k+2k) + (-4-k)(2-2k-2k) = 0` `rArr k(4k -6) + (-k+1)*4 +(-4-k) (2-4k) = 0` `rArr 4k^(2) - 6k - 4k + 4 + 4k^(2) + 16k - 2k - 8 = 0` `rArr 8k^(2) + 4k - 4 = 0` `rArr 2k^(2) + k -1 = 0 " " rArr (k +1)(2k-1) = 0` `rArr k = (1)/(2), -1` |
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