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`l isum_(n-gtoo)sum_(r=1)^n1/(sqrt(4n^2-r^2))`A. `(pi)/(6)`B. `(pi)/(4)`C. `(pi)/(3)`D. `(pi)/(2)` |
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Answer» Correct Answer - A `S=underset(nrarroo)(lim)sum_(r=0)^(n-1)(1)/(sqrt(4n^(2)-r^(2)))` `rArr" "S=(1)/(n)underset(nrarroo)(lim)sum_(r=0)^(n-1)(1)/(sqrt(2^(2)-((r)/(n))^(2)))` `rArr" "S=int_(0)^(1)(dx)/(sqrt(2^(2)-x^(2)))` `rArr" "S=[sin^(-1).(x)/(2)]_(0)^(1)=sin^(-1).(1)/(2)-sin^(-1)` `rArr" "S=(pi)/(6)` |
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