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Leg `f(x)=x^4-4x^3+6x^2-4x+1.`Then,`f`increase on `[1,oo]``f`decreases on `[1,oo]``f`has a minimum at `x=1``f`has neither maximum nor minimumA. f increases on `[1,oo]`B. f decreases on `[1,oo]`C. f has a minimum at x=1D. f has neither maximum nor minimum |
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Answer» Correct Answer - 1,3 f(x)=`4(x^(3)=3x^(2)+3x-1)=4(x-1)^(3)gt0 for x gt1` Hence f increases in `[1,oo)` Moreover f(x)`lt0 for x lt 1` Hence f has a minimum at x =1 |
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