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                                    Let a,b,c,d be real numbers such that |a-b|=2, |b-c|=3, |c-d|=4 Then the sum of all possible values of |a-d|=A. `9`B. `18`C. `24`D. `30` | 
                            
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Answer» Correct Answer - B `(b)` `|a-b|=2impliesa-b=+2` `|b-c|=3impliesb-c=+-3` `|c-d|=4impliesc-d=+-4` Possible values of `a-d` are `+-9`, `+-5`, `+-3`, `+-1` `:. |a-d|=9,5,3,1` Sum `=18`  | 
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