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Let `a`, `b gt 0` satisfies `a^(3)+b^(3)=a-b`. ThenA. `a^(2)+b^(2)=1`B. `a^(2)+ab+b^(2) lt 1`C. `a^(2)+b^(2) gt 1`D. none of these |
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Answer» Correct Answer - B `(b)` `a^(2)+ab+b^(2)=(a^(3)-b^(3))/(a-b)=(a^(3)-b^(3))/(a^(3)+b^(3)) lt 1`. |
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