1.

Let `f(x)`be defined as`f(x)={tan^(-1)alpha-5x^2,0

Answer» Correct Answer - `alpha lt -tan 1`
`f(x)={{:(tan^(-1) alpha-5x^(2),0ltxlt),(-6x,xge1):}`
f(1)=-6
for maximum at x=1
`underset(xrarr1)lim f(x)=tan^(-1)alpha -5lt-6`
or `tan^(-1)alphalt-1 or alpha-tan 1`


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