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Let `f(x)`be defined as`f(x)={tan^(-1)alpha-5x^2,0 |
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Answer» Correct Answer - `alpha lt -tan 1` `f(x)={{:(tan^(-1) alpha-5x^(2),0ltxlt),(-6x,xge1):}` f(1)=-6 for maximum at x=1 `underset(xrarr1)lim f(x)=tan^(-1)alpha -5lt-6` or `tan^(-1)alphalt-1 or alpha-tan 1` |
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