1.

Let `f(x)=p[x]+qe^(-[x])+r|x|^(2)`, where p,q and r are real constants, If f(x) is differential at x=0. Then,A. `q=0,r=0, p in R`B. `p=0,r=0, q in R`C. `p=0,q=0, r in R`D. none of these

Answer» Correct Answer - C
We have `f(x)=p[x]+qe^(-[x])+rx^(2)`
Since, [x] and [x] are not differentiable at x=0. Therefore, f(x) will be differentiable at x=0 only when p=q=0


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