InterviewSolution
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InterviewSolution
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let `y=t^(10)+1,` and `x=t^8+1,` then `(d^2y)/(dx^2)` isA. `(5)/(2)t`B. `20t^(8)`C. `(5)/(16t^(6))`D. none of these |
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Answer» `"Here, "y=t^(10)+1 and x=t^(8) +1` `therefore" "t^(8)=x-1 or t^(2)=(x-1)^(1//4)` `"So, "y=(x-1)^(5//4)+1` Differentiating both sides w.r.t. x, we get `(dy)/(dx)=(5)/(4)(x-1)^(1//4)` Again, differentiating both sides w.r.t. x, we get `(d^(2)y)/(dx^(2))=(5)/(16)(x-1)^(-3//4)=(5)/(16(x-1)^(3//4))=(5)/(16(t^(2))^(3))=(5)/(16t^(6))` |
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