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Light from a point source in air falls on a spherical glass surface. If `mu = 1.5`, and radius of curvature `= 20 cm`, the distance of light source from the glass surface is `100 cm` , at what position will the image be formed ? (NCERT Solved Example) |
Answer» Here, `mu_(2) = 1.5, mu_(1) = 1` , `R = 20 cm`, `u = -100 cm, v = ?` As light goes from air (rarer medium) to glass (denser medium), therefore, `-(mu_(1))/(u) + (mu_(2))/(v) = (mu_(2) - mu_(1))/(R )` `-(1)/(-100) + (1.5)/(v) = (1.5 - 1)/(20) = (1)/(40)` `(3)/(2 v) = (1)/(40) - (1)/(100) = (5 - 2)/(200) = (3)/(200) = 100cm` `:.` The image is formed at a distance of `100cm` from the glass surface, in the direction of incident light. |
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