1.

Light from a point source in air falls on a spherical glass surface. If `mu = 1.5`, and radius of curvature `= 20 cm`, the distance of light source from the glass surface is `100 cm` , at what position will the image be formed ? (NCERT Solved Example)

Answer» Here, `mu_(2) = 1.5, mu_(1) = 1` , `R = 20 cm`,
`u = -100 cm, v = ?`
As light goes from air (rarer medium) to glass (denser medium), therefore,
`-(mu_(1))/(u) + (mu_(2))/(v) = (mu_(2) - mu_(1))/(R )`
`-(1)/(-100) + (1.5)/(v) = (1.5 - 1)/(20) = (1)/(40)`
`(3)/(2 v) = (1)/(40) - (1)/(100) = (5 - 2)/(200) = (3)/(200) = 100cm`
`:.` The image is formed at a distance of `100cm` from the glass surface, in the direction of incident light.


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