1.

Light of wavelength ` 300 xx 10^(-9)` m strikes a metal surface with photoeoctric work function of ` 2. 13 eV`. Find out the kinetic enrgy fo the most energetic photoelectron .

Answer» Energy of photon = Work function + Kinetic enrgy Kinetic energy = Energy of photo -Work function
` = (hc)/(lambda) - "Work function"`
`(therefore "Work function" = 2 . 13 eV = 2 . 13 xx 1. 6 xx 10^(-19) J)`
`=[(6.626 xx 10^(-34) xx 3.0 xx 10^8)/(300 xx 10^(-9))] - 2 . 13 xx 1. 6 xx 10^(-19)`
` 6.626 xx 10^(-19) - 3. 41 xx 10 ^(-19) `
` K.E . = 3 . 216 xx 10^(-19) J`
The is the kinetic energy of most energyetic photoelectron.


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