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Light travels with a velocity 1.5xx10^(8) m/sin a medium. On entering secon medium its velocity becomes 0.75xx10^(8) m/s. What is the refractive index of the second medium with respect to the first medium ?

Answer»

SOLUTION :Given : `v_(1) =1.5xx10^(8)` m/s
`v_(2)=0.75xx10^(8)` m/s
To find : `""_(2)n_(1)`
Solution : `""_(2)n_(1)=(1.5xx10^(8))/(0.75xx10^(8))=2`
The refractive index of the second MEDIUM with respect to thefirst medium is 2


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