InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
`lim_(x->0)sin(picos^2x)/(x^2)=` |
|
Answer» `Lim_(x->0) sin(picos^2x)/x^2` `=Lim_(x->0) sin(pi(1-sin^2x))/x^2` `=Lim_(x->0) sin(pi-pisin^2x)/x^2` `=Lim_(x->0) sin(pisin^2x)/x^2` `=Lim_(x->0) sin(pisin^2x)/(pisin^2x)*(pisin^2x)/x^2` We know, `Lim_(x->0) sin(f(x))/(f(x)) = 1` So, our limits becomes, `=1*pi(1) = pi` `:. Lim_(x->0) sin(picos^2x)/x^2 = pi` |
|