1.

`lim_(xrarr0) (sinax+bx)/(ax+si nbx),a,b,a+bne0`

Answer» `underset(xrarr0)"lim"(sin ax+bx)/(dx+sinbx)(a,b,a+bne0)((0)/(0))`
`=underset(xrarr0)"lim"((sinax)/(x)+b)/(a+(sinbx)/(x))`
(Divide numerator/denominator by x)


Discussion

No Comment Found